x^2+2x-0.49=0

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Solution for x^2+2x-0.49=0 equation: 



x^2+2x-0.49=0

a = 1; b = 2; c = -0.49;
Δ = b2-4ac
Δ = 22-4·1·(-0.49)
Δ = 5.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{5.96}}{2*1}=\frac{-2-\sqrt{5.96}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{5.96}}{2*1}=\frac{-2+\sqrt{5.96}}{2}
$

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